Friday, March 20, 2020
Woodrow Wilson Essays - Presidency Of Woodrow Wilson, Free Essays
Woodrow Wilson Essays - Presidency Of Woodrow Wilson, Free Essays Woodrow Wilson Woodrow Wilson -Born in Virginia in 1856 and raised in the South - Democratic president whose election in 1912 ushered in a second wave of progressive reforms on the national level served as US president until 1921. New Nationalism, New Freedom Central to Theodore Roosevelts Campaign was a scheme Called ___________ ____________ which envisioned an era of national unity in which government would coordinate and regulate economic activity. Wilsons proposal , the __________ ___________ was more idealistic. He argued that concentrated power threatened individual liberty and that monopolizes should be broken to ensure a free market place. Federal Trade commission This agency was formed in 1914 to ensure fair trade and practices. Underwood Tariff 1913 This encouraged importation of cheaper foreign goods.. Federal Reserve Act 1913 This established the nations first banking system since 1836. Adamson Act 1916 A United States federal law passed in 1916 that established an eight-hour workday, with additional pay for overtime work, for interstate railroad workers Clayton Anti-Trust Act
Wednesday, March 4, 2020
History and Properties of M-Theory
History and Properties of M-Theory M-Theory is the name for a unified version of string theory, proposed in 1995 by the physicist Edward Witten. At the time of the proposal, there were 5 variations of string theory, but Witten put forth the idea that each was a manifestation of a single underlying theory. Witten and others identified several forms of duality between the theories which, together with certain assumptions about the nature of the universe, could allow for them to all be one single theory: M-Theory. One of the major components of M-Theory is that it required adding yet another dimension on top of the already-numerous extra dimensions of string theory so that the relationships between the theories could be worked out. The Second String Theory Revolution In the 1980s and early 1990s, string theory had reached something of a problem due to an abundance of riches. By applying supersymmetry to string theory, into the combined superstring theory, physicists (including Witten himself) had explored the possible structures of these theories, and the resulting work had shown 5 distinct versions of superstring theory. Research further showed that you could use certain forms of mathematical transformations, called S-duality and T-duality,à between the different versions of string theory. Physicists were at a lossà At a physics conference on string theory, held at the University of Southern California in spring of 1995, Edward Witten proposed his conjecture that these dualities be taken seriously. What if, he suggested, the physical meaning of these theories is that the different approaches to string theory were different ways of mathematically expressing the same underlying theory. Though he did not have the details of that underlying theory mapped out, he suggested the name for it, M-Theory. Part of the idea at the heart of string theory itself is that the four dimensions (3 space dimensions and one time dimension) of our observed universe can be explained by thinking of the universe as having 10 dimensions, but then compactifying 6 of those dimensions up into a sub-microscopic scale that is never observed. Indeed, Witten himself was one of the people who had developed this method back in the early 1980s! He now suggested doing the same thing, by assuming additional dimensions that would allow for the transformations between the different 10-dimensional string theory variants. The enthusiasm of research that sprung out of that meeting, and the attempt to derive the properties of M-Theory, inaugurated an era that some have called the second string theory revolution or second superstring revolution. Properties of M-Theory Though physicists have still not uncovered the secrets of M-Theory, they have identified several properties that the theory would have if Wittens conjecture turns out to be true: 11 dimensions of spacetimeà (these extra dimensions should not be confused with the idea in physics of a multiverse of parallel universes)contains strings and branes (originally called membranes)methods of using compactification to explain how the extra dimensions reduce to the four spacetime dimensions we observedualities and identifications within the theory that allow it to reduce to special cases of the string theories known, and ultimately into the physics we observe in our universe What does the M Stand For? It is unclear what the M in M-Theory is meant to stand for, though it is likely that it originally stood for Membrane since these had just been discovered to be a key element of string theory. Witten himself has been enigmatic on the subject, stating that the meaning of the M can be selected for taste. Possibilities include Membrane, Master, Magic, Mystery, and so on. A group of physicists, led in large part by Leonard Susskind, have developed Matrix Theory, which they believe could eventually co-opt the M if it is ever shown to be true. Is M-Theory True? M-Theory, like the variants of string theory, has the problem that it is at present makes no real predictions that can be tested in an attempt to confirm or refute the theory. Many theoretical physicists continue to research this area, but when you have over two decades of research with no solid results, enthusiasm undoubtedly wanes a bit. There is no evidence, however, that strong argues that Wittens M-Theory conjecture is false, either. This may be a case where a failure to disprove the theory, such as by showing it to be internally contradictory or inconsistent in some way, is the best that physicists can hope for at the time being.
Sunday, February 16, 2020
System Modelling Assignment Example | Topics and Well Written Essays - 1500 words
System Modelling - Assignment Example The represented logical structures abstract the inputs, outputs and data flows in the system. In other words the process and representations in the system are models. Keywords: Web-based, management, JavaScript, Remote, Information Technology Sequence Diagram to add a book into the library database: Collaboration Diagram to add a new book to the library Alternative solutions In library management, the software application solutions available are numerous. For instance, one can build a virtual library, use the manual system, use a cloud application for the library management etc. Another additional option is to purchase an information system off the shelf. This means that it is not a tailor made solution; therefore it may pose incompatibility problems. All these systems require careful evaluation and assessment, in order to come up with the most cost effective option that also caters for the organisational needs (Lesley, 2006). The process of system analysis and design should cover th e business, or operational aspect of the organisation. This is in order to guarantee that the system makes ââ¬Å"business senseâ⬠. The definition for business sense is a system that balances the organisational needs and the user requirements. This ensures that the end solution does not implement the business requirements and leave the user functionality (Hickie, Greasley & Bocij, 2008). Proposed system description Based on the requirements of the organisation, the system desired should introduce the concepts of automatic record keeping and digitize the library processes. The system will provide the functionality to add new books, update book details and manage non-book items. In addition, the system shall display referral links to electronic book sites and also provide purchase links. Further, the system proposed will also act as an information collaboration platform. This will coordinate the communication between the staff/management and the library members (Boehm, & Petty 19 99). Alternative solution one: Virtual Library The virtual library solution provides a fully functional system that manages issuing, sale and reading of electronic books. It can be accessed via the internet by users. However, the users need to register with the library for accounts and also pay a small subscription fee. The virtual library has the advantage of cost. It is cheap to implement it as a solution and it has minimal infrastructural needs. Berndt (2002) explains that the main disadvantage of the virtual library is that it cannot hold any physical objects given that it runs on the system. The Swansea Docklands society needs a physical access and the online system is intended to bring efficiency and convenience. To publicise their library internet marketing may work, but the virtual library will not be the desired product. Alternative solution two: Cloud Application Boehm, & Petty (1999) points that cloud computing is among the most recent technology developments in the IT wo rld that has revolutionised communication, data storage and. This technology squarely fits the needs of a museum and library management system. End users are able to access cloud based library manageme
Monday, February 3, 2020
Event Risk Management Assignment Example | Topics and Well Written Essays - 1500 words
Event Risk Management - Assignment Example This is coordinated by the risk manager who controls the number of medical personnel to be present as well as the amount of equipments to be used. The equipments should be placed before the event begins. The personnel should also remain in place until the special event is over. There should be a communication plan to avoid conflict of interest in case of fire outbreak. According to Taylor (2002) the risk manager should plan for ambulances in case something happens. That is, the number of ambulances to be used as well as well as their passage to and fro the special event compound. People who reject medical attention should be documented to avoid legal issues later. There should also be a shelter to cater for the victims and medical personnel during rainy, sunny or extreme windy conditions. The medical official vehicles should also be secured to avoid cases of vandalism or theft. Fire incidences can quickly be controlled by the use of smoke alarms. Smoke alarms and sprinkler systems should be checked to reduce the spread of fire. Use of an evacuation plan is highly necessary especially for the old, disabled and children. The evacuation plan should be read and explained to the participants in advance. The evacuation plan should be pre tested and discussed by the various fire officials to prevent the actual fire incidence. The evacueesââ¬â¢ routes should be demarcated to necessitate ease during evacuation. Biochemical precautions should be taken care-of by consultations with the relevant experts. Biochemical hazards increase the intensity of the fire and it complicates the extinction of the fire (Taylor, 2002). The risk management team should ensure emergency power backups and phones are put in place to cater for emergences when need arises. Poison can be minimized by provision of hotline numbers for all poison control
Saturday, January 25, 2020
Geometrical Application Of Ordinary Differential Equation
Geometrical Application Of Ordinary Differential Equation Many practical problems in science and engineering are formulated by finding how one quantity is related to, or depends upon, one or more (other) quantities defined In the problem. Often, it is easier to model a relation between the rates of changes in the variable rather than between the variables themselves. This study of this relationship gives rise to differential equation. Derivatives can always be interpreted as rate. For example, if x is a function of t then dx/dt is the rate of x with respect to t. if x denotes the displacement of a particle, then dx/dt represents the velocity of the particle. If x represents the electric charge then dx/dt represents the flow of charge that is the current. Derivatives of higher orders represents rate of rates. If x denotes the displacement of particle, then d2x/dt2 represents the accelerations. A differential equation can be defined as an equation containing derivatives of various orders and variables .differential equation which involves one independent variable are called ordinary differential equation. If the differential equation involves more than one independent variable and partial derivatives of the dependent variable with respect to them, than it is called partial differential equation. Explanation:- Let y be the dependent variable and x be the independent variable. So the system can be denoted as dy/dx= y , d2y/dx2=y Some Example of Ordinary Differential equation y=62 y+16y =2x x2y-xy+6y=log x yy+ y2 = x2 Introduction to differential equation, and solving linear differential equations using operator method:- In this Term paper, I will first introduce what differential equation is? Separable first order differential equation will be solved. Then the integrating factor will be taught to solve linear differential equation of the first degree. The auxiliary equation (or characteristic equation) will be introduced to solve homogeneous linear equations, and then operator method will be taught finally to solve non-homogeneous linear equations. This term paper assumes readers familiar with basic of calculus, like differentiation and integration. What is differential equation? A differential equation is an equation which contains derivatives. Here are some examples: In these equations, y is an unknown function depends on x which we would like to solve. These kind of equations are very important in different fields, like in chemistry describing rate of reaction, physics describing equation of motion, etc. Therefore, able to solve these equations analytically enables us to understand many natural process. The above equations are known as ordinary differential equations(ODE) since they only contain derivatives with respect to one variable, x. (note that the equations hold for all values of x) In mathematics, an ordinary differential equation (or ODE) is a relation that contains functions of only one independent variable, and one or more of their derivatives with respect to that variable. A simple example is Newtons second law of motion, which leads to the differential equation for the motion of a particle of constant mass m. In general, the force F depends upon the position x(t) of the particle at time t, and thus the unknown function x(t) appears on both sides of the differential equation, as is indicated in the notation F(x(t)). Ordinary differential equations are distinguished from partial differential equations, which involve partial derivatives of functions of several variables. Ordinary differential equations arise in many different contexts including geometry, mechanics, astronomy and population modelling. Many famous mathematicians have studied differential equations and contributed to the field, including Newton, Leibniz, the Bernoulli family, Riccati, Clairaut, dAlembert and Euler. Much study has been devoted to the solution of ordinary differential equations. In the case where the equation is linear, it can be solved by analytical methods. Unfortunately, most of the interesting differential equations are non-linear and, with a few exceptions, cannot be solved exactly. Approximate solutions are arrived at using computer approximations. The trajectory of a projectile launched from a cannon follows a curve determined by an ordinary differential equation that is derived from Newtons second law. Ordinary differential equation Let y be an unknown function in x with y(n) the nth derivative of y, and let F be a given function then an equation of the form is called an ordinary differential equation (ODE) of order n. If y is an unknown vector valued function , it is called a system of ordinary differential equations of dimension m (in this case, F : à ¢Ã¢â¬Å¾Ã mn+1à ¢Ã¢â¬ ââ¬â¢ à ¢Ã¢â¬Å¾Ã m). More generally, an implicit ordinary differential equation of order n has the form where F : à ¢Ã¢â¬Å¾Ã n+2à ¢Ã¢â¬ ââ¬â¢ à ¢Ã¢â¬Å¾Ã depends on y(n). To distinguish the above case from this one, an equation of the form is called an explicit differential equation. A differential equation not depending on x is called autonomous. A differential equation is said to be linear if F can be written as a linear combination of the derivatives of y together with a constant term, all possibly depending on x: with ai(x) and r(x) continuous functions in x. The function r(x) is called the source term; if r(x)=0 then the linear differential equation is called homogeneous, otherwise it is called non-homogeneous or inhomogeneous. Solutions Given a differential equation a function u: I à ¢Ã
ââ¬Å¡ R à ¢Ã¢â¬ ââ¬â¢ R is called the solution or integral curve for F, if u is n-times differentiable on I, and Given two solutions u: J à ¢Ã
ââ¬Å¡ R à ¢Ã¢â¬ ââ¬â¢ R and v: I à ¢Ã
ââ¬Å¡ R à ¢Ã¢â¬ ââ¬â¢ R, u is called an extension of v if I à ¢Ã
ââ¬Å¡ J and A solution which has no extension is called a global solution. Terminology Partial differential equations These are equations which involves more than one independent variable. For instance: Partial differential equations(PDE) are significantly more difficult than ODE, and we wont talk about it at this moment. Order Order of a differential equations is the order of the highest derivative in the equation. Order 1: Order 2: Degree The degree of a differential equation is the degree of the highest derivative in the equation. Degree 1: Degree 2: Separable 1st order ODE If the ODE is in the following form, the solution can be found using integration easily: Example:- In the study of partial differentiation, recall that a function of two variables that equals a constant, describes the points in the 3-D plane with the same potential; . The curves that connect the points with the same potential are called level curves and have the value of c. A contour map is a level curve graph where common elevations are connected giving a 2-D representation of a 3-D reality. Using a LiveMath 3-D graph theory you can plot such a function along with the level curves describing the contours associated with that function. The picture below uses the following function to demonstrate this (here is a LiveMath plug-in animation of the graph below). In general terms, this type of equation is represented by the following: It describes the level curves and is the solution to the following differential equation. The equation below is just the total derivative of the function above. Because it is the total derivative of some function z(x,y) it is called an Exact Differential Equation. To help understand how to solve these types of equations you will look at the solution first and then analyze how to back into that solution. In this example you will take the total derivative of a function and analyze its parts. Then you will take this new equation (a differential equation now) and, knowing the answer, describe the method used to solve it. Input the following equation: To take a total derivative in LiveMath, first input the differential operator d times z (d*z). Input this into a second Prop and substitute the equation into it. Collect common terms on the RHS and Expand the coefficients of the differentials for the final answer. After setting the RHS equal to zero you will have a differential equation to solve. Notice how the coefficients are neither separable, homogeneous, nor are they linear. To help analyze this equation, label the coefficient of dx as M and the coefficient of dy as N. Both are functions of x and y so place the equation in the following form. The total derivative of a function is obtained by adding the partial derivatives of the coefficients. This is done with the equation below. Set up our notebook in the following manner: Perform the substitutions to give the partial derivatives. we can see that differential equations of this type are Exact. They are immediate derivatives of another function. You know this is true in this example because you developed the equation below by taking the derivative of the original function. we can describe an Exact Differential Equation as an equation whose dx coefficient is the partial derivative with respect to x of some function f(x,y) and whose dy coefficient is the partial derivative with respect to y of the SAME function. Since you dry-labed the last example you know what this equation, z=f(x,y), is. This will not be the case as you look to solve these problems though, so you need to find a way of determining that an equation is exact, then you will know that M and N are related to the solution equation in this way! Using the fact that these partial derivatives are of the same function will be the key to the method used to solve these equations. To test a differential equation for exactness, follow the method described in the next example. Test for Exactness This example demonstrates the test for exactness of the same equation used in the previous example. First input the differential equation as shown below. Remember to include an Independence Declaration inside the same case theory the test is performed. To test for exactness, equate the partial derivative with respect to y of M and the partial derivative with respect to x of N. Notice that these partials are with respect to the exact opposite variables as those used to determine the total derivative in the last example. The reason for this will become clear to you later when you derive this test. Set up the partial derivatives and solve by substituting M and N into the partial derivative Ops. The fact that they are equal means that the differential equation is exact! Method of Solution: To solve these types of equations you will need to take one or the other coefficient and go backwards to determine the solution. You can take either M or N to do this, it is up to you. For this example try using M. Solution Method First, set up an equation equating the unknown function, named , to an integral of M plus some unknown function of y. Call this function u for the time being. The reason you do this is the fact that to get M, the partial derivative was taken of the unknown function with respect to x. You will try to back into the answer by integrating M. This is not automatic though, because of the fact that when a partial derivative is performed, one of the variables is treated as a constant and therefore drops out (the derivative of a constant is = 0). Below this derivative is displayed again. We will not get back the function by integrating M, because the y term is not there! It is the constant, as is shown below where you try to get the function back by integrating M. This is very close to the answer, and with a little twist, will lead to a method that you will use to obtain the solution. Input the following props and perform the substitutions as shown. The user defined variable u is used in this case, rather than the arbitrary constant c, because you are actually looking for, what you might call, an arbitrary function. It will also be necessary later to have u defined as a variable for LiveMath to solve for the function. Now we have a potential function (), that represents the solution to the problem. To solve, the function u must be determined. If you take the partial derivative of the unknown function with respect to y this time, you will get N. By setting up the equation this way, you can then isolate u. You already know what N is, so: Next substitute the potential function into the Prop and solve for u by performing an integration. The final solution is achieved by substituting this u Prop back into the function . Since this function describes level curves, it is set equal to a constant c. The question remains, why do you take partial derivatives of M and N to determine if an equation is exact? M and N have been defined as the partial derivatives of z with respect to x and y respectively. By taking the second partial derivative of each coefficient WITH RESPECT TO THE OPPOSITE VARIABLE, the LHS of both of these equations is equal and therefore the RHS are equal too.
Friday, January 17, 2020
Officer Selection
Because of the range of duties, officers should possess certain traits: hectically agility, the ability to cope with difficult situations, well-developed writing skills, good communication skills, sound Judgment, compassion, strong powers of observation, and the ability to both exert and respect commands of authority. Minimum Requirements Every department sets its own standards when considering candidates for police officers, however most departments require a series of minimum standards which perspective applicants must have.All applicants must be at least 21 years of age and have or be eligible to receive a driver's license because their primary duty Is patrol, ND they must be able to drive to respond to Incidents. Police officers must also be able to possess a firearm. In order to qualify to own a firearm, a person must be at least twenty-one years old. Applicants must also have no Felony convictions. Convicted felons also are prohibited from possessing a firearm, which thereby ba rs them from becoming police officers.Individuals with domestic violence convictions are no longer able to possess a firearm, thereby prohibiting them from becoming police officers as well (Grant & Terry, 2009). Finally many police departments now have educational standards for recruits. Nearly all departments require officers to have at least a high school diploma. And many require at least some college credits. Written Examination The written examination is the first step in becoming a police officer once a formal application has been submitted.The test varies by department, but It might be a civil service exam, an exam produced by the individual police department, or one produced by a private testing company. The exam does not test specific legal or criminal Justice knowledge, but rather evaluates the candidate's basic reading, writing, and comprehension skills. The exam will likely contain a number of different sections, whereby the candidate must be able to understand and write In English, write a sample essay, understand basic mathematics, memorize facts, show sound 1 OFF reasoning Ana logic, Ana analyze potential scenarios .For clamatorial ten written examination is developed by the California Commission on Peace Officer Standards and Training (POST) and measures reading comprehension and writing abilities (caperers. Com, 2011). Departmental Interview Departmental Interview will evaluate the applicant's interpersonal skills, problem solving, oral communication and other abilities not tested by other examination components. The interview is not scored; however, the interview panel will make recommendations regarding who should proceed in the final hiring process.The interview can be structured, unstructured, or a combination or both. In a structured interview, the candidate is asked a series of questions regarding the Job and his or her specific abilities. Structured questions such as ââ¬Å"Do you drink alcoholâ⬠, usually require specified answers direct answers. The alternative to this would be to conduct a semi structured interview with open ended questions on particular topics. Structured interviews allow for a better comparison of candidates on specific topics, pen-ended questions are likely to elicit more information.Though the candidate must pass all phases of the selection process in order to be hired as a police officer, the interview process is critical in the assessment of the candidate's attitudes, appearance, and demeanor. Physical Ability Examination The Physical Ability Examination will measure physical performance through a series of exercises that will be administered on a pass/fail basis. Measuring a police candidate's level of physical agility is a crucial part of the selection process, although the physical agility test has been controversial and has undergone significant hangs since its inception (Grant & Terry, 2009).The Physical Ability Examination has gone through many changes. Until the sass's the test required applicants to demonstrate substantial upper body strength which kept many women from completing the test successfully thereby eliminating them from the candidate pool. The introduction of Title VII in 1972 as well as the Equal Employment Opportunity Commission (EEOC) guidelines on sex discrimination barred the refusal to hire a female applicant because of characteristics attributed to women as a class and thus the physical agility tests have changed considerably in the past few decades.Psychological and Polygraph Tests A Polygraph Examination is used to verify the veracity and accuracy of information submitted by candidates regarding, but not necessarily limited to: use of controlled substances; driving, criminal, medical and employment history; and other Job-related factors. The polygraph works by recording involuntary physiological changes in the body that occur when a person is partaking in conscious deceit.The purpose of the psychological screening process is to measur e intelligence and to identify personality characteristics and any mental disorders that may lead to problematic behavior in he future (Grant & Terry, 2009). Psychological screening, particularly those measuring conscientiousness, emotional stability, agreeableness, and integrity ââ¬â have been shown to aid in the prediction of on-the-Job performance across a wide variety of occupations, including peace officers (POST. A. Gob, 2011) It is important to screen out individuals who may exhibit mental or personality deficits, because police officers interact with individuals on a daily basis and often in high-stress situations. Background Investigation I en employment, connecter Ana Docudrama Investigation consists AT a tongue duty of the candidate's history prior to appointment to determine fitness for this employment.Reasons for rejection include use of controlled substances, felony convictions, repeated or serious violations of the law, inability to work cooperatively with co-work ers, inability to accept supervision, or other relevant factors. Candidates who are disqualified during the background investigation process must wait two years from the date of disqualification before they may reapply to take the Police Officer examination.Candidates who are disqualified because of uncorrectable deiced problems, serious drug abuse or because of criminal records may possibly not be allowed to reapply. Training Once a police candidate has passed through the selection process, he or she is hired on probation, a trial period of one or two years during which the officer is evaluated. This probationary period begins with training at the police academy, a school where officers learn on-the-Job techniques prior to receiving full police powers.Officers must train at the academy for up to 1,100 hours, and they receive full pay and benefits from the time they enter the academy (Grant & Terry, 2009). Training is rigorous, demanding and exhausting. It is also a rewarding life-c hanging experience. New officers learn how much they are capable of by succeeding at seemingly impossible challenges, both physical and mental Mainland. Com, 2011). While in the academy, the officer receives educational as well as practical physical The Los Angles Police Department (LAPS) Academy Curriculum includes training.Academics, which encompasses arrest and booking procedures, preliminary investigation techniques, radio and communications, report writing, traffic investigation, and traffic enforcement, Driving, which includes emergency procedures ND defensive driving techniques, Firearms Training, which trains candidates in effective and safe use of police issued firearms, Law, which covers search and seizure, evidence, laws of arrest, crimes against persons and property, sex crimes, crimes against children, and other general criminal statutes falling under the California Penal Code, Los Angles Municipal Code, Welfare and Institutions Code, and Federal Laws, and finally physi cal training which builds strength and endurance through physical conditioning while promoting a positive attitude toward a fitness lifestyle. It also encompasses training in physical arrest techniques, controls, and weaponless defense Mainland. Com, 2011).Development Once a new police officer leaves the academy, they are assigned a field training officer (FOOT) who assists the new officer to acclimate into the police culture, or experience the solicitation process. Solicitation involves learning the values, social processes, and behaviors associated with the police institution. It involves the patterns of interaction that depend on the relations of individuals in particular settings (Grant & Terry, 2009). Foot can have a significant influence over new officers ND assist them in dealing with the inevitable stress and cynicism of the Job. Conclusion Selecting qualified police officers is a lengthy, competitive process, involving multiple phases. Candidates are exposed too battery of tests both physically and mentally to ascertain their overall qualifications and abilities.
Thursday, January 9, 2020
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